Review To construct a solenoid, you wrap insulated wire uniformly around a plastic tube 12 cm in diameter and 60 cm in length. You would like a 2.0 −A current to produce a 2.6 −kG magnetic field inside your solenoid. Part A What is the total length of wire you will need to meet these specifications? Express your answer using two significant figures.

Answer:46.80 mStep-by-step explanation:Given:Magnetic field, B = 2.6 kG = 2600 G = 0.26TDiameter of the plastic tube = 12 cm = 0.12mLength of the plastic tube = 60 cmCurrent, I = 2 AThe formula for the magnetic field (B) at the center of a solenoid is calculated as: [tex]B=\frac{\mu_oNI}{L}[/tex]where,I = currentN = TurnsL = Length [tex]\mu_o[/tex]= permeability of the free spaceon substituting the values in the above equation, we get [tex]0.26=\frac{4\pi \times10^{-7}\times N\times 2}{0.6}[/tex]orN = 62070.42 Turnsalso, each turn is a circumference of the plastic tube. The circumference of the plastic tube, C = 2π×0.12 =  0.7539 m Thus, The total length of the wire required, L = (62070.42) × 0.7539 m = 46799.99 ≈ 46800 m  = 46.80 km